Government Jobs: Government of India has recruited 6060 posts for 10th pass

Government Jobs: Government of India has recruited 6060 posts for 10th pass, such selection will be done

In the 10th examination, candidates should pass with 50 percent marks. Also it is necessary to have 40 percent marks in Math and Science.

Government Jobs: Government of India has recruited 6060 posts for 10th pass


OFB Recruitment 2020: Ordnance Factory Board has sought application for apprentice in 6060 posts for 10th pass candidates. There are 3847 ITIs and 2219 non-ITI posts. Interested candidates can apply for these posts from 10 January to 9 February 2020. Selected candidates for these posts will be appointed in Madhya Pradesh, Chandigarh, Maharashtra, Odisha, Uttar Pradesh, Uttarakhand, Tamil Nadu and West Bengal.

Description of posts

Total Posts - 6060
ITI - 3847
Non ITI - 2219

Educational Qualifications
- The candidate must pass the Class X examination from a recognized school education board. Applicant must have National Trade Certificate or National Apprenticeship Certificate (NAC) from National Council of Vocational Training.
- Non-ITI candidates are required to pass 10th standard along with 50 percent marks in it. It is mandatory to have 40 per cent marks in Mathematics and Science.

Age Range
The minimum age of the candidate should be 15 years and the maximum age should be 24 years. Age limit will be calculated as on 09 February 2020.

Selection Process
The selection of candidates for these posts will be on the basis of merit. Separate merit list will be made for both ITIs and non-ITIs.

See details here
Applicants can visit this ofb.gov.in/ for more information.

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